1 pt
Chapter: 5
Standard: A.REI.1
DOK: 2

1.

Sally picks any number between 1 and 20, doubles it, adds 6, divides by 2, subtracts 3 and gets the number she started with. Why does this work?

A

$$\text{Writingthisasanalgebraicexpressionshowsusthat}\frac{2(x+6)}{2}-3=x+6-3=x+3.$$

B

$$\text{Writingthisasanalgebraicexpressionshowsusthat}\frac{(2x)}{2}+6-3=x+6-3=x+3.$$

C

$$\text{Writingthisasanalgebraicexpressionshowsusthat}2x+\frac{6}{2}-3=2x+3-3=2x.$$

D

$$\text{Writingthisasanalgebraicexpressionshowsusthat}\frac{\left(2x+6\right)}{2}-3=x+3-3=x.$$

1 pt
Chapter: 5
Standard: A.CED.1
DOK: 2

3.

Solve the compound inequality: $$-3\le 2x+1\le 5$$.

A

$$\u20132\le x\le 2$$

B

$$-3\le x\le 5$$

C

$$-5\le x\le 3$$

D

No solution

1 pt
Chapter: 6
Standard: A.CED.4
DOK: 2

6.

The monthly cost of Marilyn's cell phone is represented by the formula P(*x*) = 0.1*x* + $89.50. This equation expresses the total cell phone charges, with *x* representing the total number of text messages. Marilyn knows the monthly cost of her cell phone and wants to find the number of text messages. Which equation should Marilyn use to find the number of text messages?

A

*x* = 10P(*x*) – 8.95

B

*x* = – 0.1P(*x*) + 8.95

C

*x* = 0.1P(*x*) – 895

D

*x* = 10P(*x*) – 895

1 pt
Chapter: 9
Standard: F.BF.3
DOK: 2

27.

What is the difference between the graphs of $$f(x)={2}^{x}-2\text{and}g(x)={2}^{x-2}\text{?}$$

A

$$f(x)$$ has a vertical translation in the opposite direction to the vertical translation of $$g(x)$$.

B

Nothing is different about the two graphs.

C

$$f(x)$$ has a horizontal translation, while $$g(x)$$ has a vertical translation.

D

$$f(x)$$ has a vertical translation, while $$g(x)$$ has a horizontal translation.

1 pt
Chapter: 10
Standard: F.LE.2
DOK: 3

30.

Silly City has a population of 95,000 in 2003. The population increases by 2.3% annually from the previous year's population. Write a function that models the population of Silly City. Then use this function to predict the population of Silly City in 2020.

A

The initial population was 95,000. It is given that the population grows each year by 2.3%, so we need to multiply 95,000 by 1.023 for each year $$x$$ of growth. The 1 is necessary part of the calculation because it accounts for the presence of the initial population, and adds growth per year, giving the current population. The population in 2020 can be found by substituting 17 in for $$x$$. Recall that $$x=0$$ indicated year 2003. So, $$P(17)=95,000{(1.023)}^{17}\approx 139,833$$.

B

The initial population was 95,000. It is given that the population declines each year by 2.3%, so we need to multiply 95,000 by 0.023 for each year $$x$$ of growth. The population in 2020 can be found by substituting 0 in for $$x$$. Recall that $$x=0$$ indicated year 2003. So, $$P(0)=95,000{(0.023)}^{0}\approx 95,000$$.

C

The initial population was 95,000. It is given that the population grows each year by 2.3%, so we need to multiply 95,000 by 0.023 for each year $$x$$ of growth. The population in 2020 can be found by substituting 17 in for $$x$$. Recall that $$x=0$$ indicated year 2003. So, $$P(17)=95,000{(0.023)}^{17}\approx 149,705$$.

D

The initial population was 95,000. It is given that the population grows each year by 2.3%, so we need to multiply 95,000 by $$(1+{2.3}^{x})$$ for each year $$x$$ of growth. The 1 is necessary part of the calculation because it accounts for the presence of the initial population, and adds growth per year, giving the current population. The population in 2020 can be found by substituting 17 in for $$x$$. Recall that $$x=0$$ indicated year 2003. So, $$P(17)=95,000(1+{2.3}^{x})\approx 130$$ billion.